9k^2-18k-10=6

Solution for 9k^2-18k-10=6 equation:

9k^2-18k-10=6

We move all terms to the left:

9k^2-18k-10-(6)=0

We add all the numbers together, and all the variables

9k^2-18k-16=0

a = 9; b = -18; c = -16;
Δ = b2-4ac
Δ = -182-4·9·(-16)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-30}{2*9}=\frac{-12}{18}
=-2/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+30}{2*9}=\frac{48}{18}
=2+2/3
$